READ Free Dumps For CISCO- 100-105
| Question ID 14609 |  
What is the subnet broadcast address of the LAN connected to Router1?
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| Option A | 192.168.8.15
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| Option B | 192.168.8.31
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| Option C | 192.168.8.63
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| Option D | 192.168.8.127
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| Correct Answer | A |
Explanation Explanation: The IP address assigned to FA0/1 is 192.168.8.9/29, making 192.168.8.15 the broadcast address.
| Question ID 14610 | Refer to the exhibit.
After configuring two interfaces on the HQ router, the network administrator notices an
error message. What must be done to fix this error?
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| Option A | The serial interface must be configured first.
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| Option B | The serial interface must use the address 192.168.1.2
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| Option C | The subnet mask of the serial interface should be changed to 255.255.255.0
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| Option D | The subnet mask of the FastEthernet interface should be changed to 255.255.255.240
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| Option E | The address of the FastEthernet interface should be changed to 192.168.1.66
|
| Correct Answer | D |
Explanation Explanation: The IP address 192.168.1.17 255.255.255.0 specifies that the address is part of the 192.168.1.0/24 subnet 24 mask bits = 255.255.255.0 28 mask bits = 255.255.255.240 192.168.1.0/24 subnet has a host range of 192.168.1.1 to 192.168.1.254 (0 being network and 255 being broadcoast) 192.168.1.17/28 subnet has a host range of 192.168.1.17 to 192.168.1.30 (16 being network and 31 being broadcast) 192.168.1.65/28 subnet has a host range of 192.168.1.65 - 192.168.1.78 (64 being network and 79 being broadcast) if fa0/0 was left as /24, you can see that the host range includes the host range of 192.168.1.64/28 which conflicts. Simply speaking, you can't overlap the subnets. By changing the subnet mask of fa0/0 to 255.255.255.240, these networks would no longer overlap.