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Question ID 13633	Refer to the exhibit. Which address and mask combination represents a summary of the routes learned by EIGRP?
Option A	192.168.25.0 255.255.255.240
Option B	192.168.25.0 255.255.255.252
Option C	192.168.25.16 255.255.255.240
Option D	192.168.25.16 255.255.255.252
Option E	192.168.25.28 255.255.255.240
Option F	192.168.25.28 255.255.255.252
Correct Answer	C

Explanation Explanation: The binary version of 20 is 10100. The binary version of 16 is 10000. The binary version of 24 is 11000. The binary version of 28 is 11100. The subnet mask is /28. The mask is 255.255.255.240. Note: From the output above, EIGRP learned 4 routes and we need to find out the summary of them: + 192.168.25.16 + 192.168.25.20 + 192.168.25.24 + 192.168.25.28 -> The increment should bE. 28 16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240. So, the best answer should be 192.168.25.16 255.255.255.240.

Question ID 13634	A router has learned three possible routes that could be used to reach a destination network. One route is from EIGRP and has a composite metric of 20514560. Another route is from OSPF with a metric of 782. The last is from RIPv2 and has a metric of 4. Which route or routes will the router install in the routing table?
Option A	the OSPF route
Option B	the EIGRP route
Option C	the RIPv2 route
Option D	all three routes
Option E	the OSPF and RIPv2 routes
Option F	Answer : B Explanation: When one route is advertised by more than one routing protocol, the router will choose to use the routing protocol which has lowest Administrative Distance. The Administrative Distances of popular routing protocols are listed below:
Correct Answer	B

Explanation

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