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READ Free Dumps For Oracle- 1z0-803





Question ID 21933

Given a java source file:
class x {
x () {}
private void one () {}
}
public class Y extends x {
Y () {}
private void two () {one();}
public static void main (string [] args) {
new Y().two ();
}}
What changes will make this code compile?

Option A

adding the public modifier to the declaration of class x

Option B

adding the protected modifier to the x() constructor

Option C

changing the private modifier on the declaration of the one() method to protected

Option D

removing the Y () constructor

Option E

removing the private modifier from the two () method

Correct Answer C
Explanation Explanation: Using the private protected, instead of the private modifier, for the declaration of the one() method, would enable the two() method to access the one() method.


Question ID 21934

Given:
#1
package handy.dandy;
public class KeyStroke {
public void typeExclamation() {
System.out.println("!")
}}
#2
package handy; /* Line 1 */
public class Greet { /* Line 2 */
public static void main(String[] args) { /* Line 3 */
String greeting = "Hello"; /* Line 4 */
System.out.print(greeting); /* Line 5 */

Keystroke stroke = new Keystroke; /* Line 6 */
stroke.typeExclamation(); /* Line 7 */
} /* Line 8 */
} /* Line 9 */
What three modifications, made independently, made to class greet, enable the code to compile and run?

Option A

Line 6 replaced with handy.dandy.keystroke stroke = new KeyStroke ( );

Option B

Line 6 replaced with handy.*.KeyStroke = new KeyStroke ( );

Option C

Line 6 replaced with handy.dandy.KeyStroke Stroke = new handy.dandy.KeyStroke();

Option D

import handy.*; added before line 1

Option E

import handy.dandy.*; added after line 1

Option F

import handy.dandy,KeyStroke; added after line 1

Correct Answer C,D,F
Explanation Explanation: Three separate solutions: C: the full class path to the method must be stated (when we have not imported the package) D: We can import the hold dandy class F: we can import the specific method

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