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Question ID 1694

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables

You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?

Option A

A.  SELECT last_name, department_name

FROM employees NATURAL JOIN departments;
 

Option B

B.    SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);
 

Option C

C.    SELECT last_name, department_name FROM employees JOIN departments ;
 

Option D

D.    SELECT last_name, department_name
FROM employees e
RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
 
 

Option E

E.    SELECT last_name, department_name
FROM employees e LEFT OUTER
JOIN departments d ON (e.department_id = d.department_id);
 

Option F

F.    SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);
 

Correct Answer E
Explanation


Question ID 1695

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.

Option A

A.  SELECT e.last_name, m.last_name, department_name

FROM employees e
LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
 

Option B

B.    SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
 

Option C

C.    SELECT last_name, manager_id, department_name
FROM employees e
JOIN departments d ON (e.department_id = d.department_id) ;
 

Option D

D.    SELECT last_name, manager_id, department_name
FROM employees e
FULL OUTER JOIN departments d ON (e.department_id = d.department_id);
 

Option E

E.    SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
 

Option F

F.    SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
 

Correct Answer B
Explanation

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