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| Question ID 6389 | An administrator is working with the 192.168.4.0 network, which has been subnetted with a /26 mask. Which two addresses can be assigned to hostswithin the same subnet? (Choose two.)
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| Option A | A. 192.168.4.61
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| Option B | 192.168.4.63
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| Option C | 192.168.4.67
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| Option D | 192.168.4.125
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| Option E | 192.168.4.128
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| Option F | 192.168.4.132
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| Correct Answer | cd |
Explanation Only the values of host with 67 and 125 fall within the range of /26 CIDR subnet mask, all others lie beyond itw
| Question ID 6390 | What is the network address for the host with IP address 192.168.23.61/28?w
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| Option A | 192.168.23.0
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| Option B | 192.168.23.32w
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| Option C | 192.168.23.48
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| Option D | . 192.168.23.56
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| Option E | 192.168.23.60
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| Correct Answer | c |
Explanation Convert bit-length prefix to quad-dotted decimal representation, then from it find the number of bits used for subnetting you can find previously calculated number of subnets by separating subnets each having value of last bit used for subnet masking Find that your IP address is in which subnet, that subnet's first address is network address and last address is broadcast address. Based on above steps the answer is option C. From the /28 we can find all information we need: Increment: 16 (/28 = 11111111.11111111.11111111.11110000) Network address: 192.168.23.48 (because 48 = 16 * 3 and 48 < 61)